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I'm trying to run Python in Sublime but I get a syntax error because it's running Python 2.7.

I tried to create a new build with 

{
  "cmd": ["/usr/bin/python3", "-u", "$file"],
  "file_regex": "^ ]*File \"(...*?)\", line ([0-9]*)",
  "selector": "source.python"

but that isn't working either. I made a new Python file with 

import sys
print("Sublime is using: ", sys.version)

and I get 

('Sublime is using: ', '2.7.16 (default, Oct 16 2019, 00:35:27) \n[GCC 4.2.1 Compatible Apple LLVM 9.0.0 (clang-900.0.31)]')

I ran whereis python3 in the terminal and nothing returned. When I did whereis python I got usr/bin/python. When I did which python 3, I got /usr/bin/python.

I have no idea what to do to fix this.

Improve this question
9
  • 1
    Did you mean to have a space in which python 3? For me, which ignores the 3 and just prints the path to python2. Commented Jan 26, 2020 at 5:34
  • yes, you're correct. the path is then /Library/Frameworks/Python.framework/Versions/3.8/bin/python3. however, my issue remains with sublime Commented Jan 26, 2020 at 5:38
  • Does /usr/bin/python3 exist? Commented Jan 26, 2020 at 5:39
  • that's the thing. when i type whereis python3 in terminal, nothing shows up and i'm not sure why or how to fix it Commented Jan 26, 2020 at 5:40
  • Wait, in comment #2 I thought you said running where python3 returns a path? Or does it return nothing? Commented Jan 26, 2020 at 5:41
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