how to convert url to string in ios/swift?

Question

In my code ios/SWIFT I an trying to read the url from a previous image that I successful saved at Storage Firebase. There is an error at instruction let url1 = url as! String I need to convert url to string but the cast doesn't work The print instruction is ok I see the correct url at log screen print(url?.absoluteURL as Any )

   let armazenamento = Storage.storage().reference()
    let imagens = armazenamento.child("imagens")
    if let imagemSelecionada=imagem.image {
        if let imagemDados = imagemSelecionada.jpegData(compressionQuality: 0.1) {
            imagens.child("\(self.idImagem).jpg").putData(imagemDados, metadata: nil, completion: {(metaDados, erro) in
                if erro == nil {
                    print("Sucess upload")
                    imagens.child("\(self.idImagem).jpg").downloadURL(completion: { (url, erro) in
                        if(erro == nil)
                        {
                            print(url?.absoluteURL as Any )
                            let url1 = url as! String
                            self.performSegue(withIdentifier: "selecionarUsuarioSegue", sender: url1)
                        }else{
                            print(err!);
                        }
                    })

"but the cast doesn't work" 1) Always copy/paste error and exception output! 2) For better help sooner, edit to add a minimal reproducible example or Short, Self Contained, Correct Example. 3) What language is this, Scala? Please add the language tag. — Andrew Thompson
– Andrew Thompson, Commented Dec 1, 2019 at 23:49
What does this have to do with Swing. Swing is a graphical UI for Java. You question has nothing to do with a graphical component. The code posted does not look like Java. Is it JavaScript? (I know JavaScript has a "let" keyword) if so, then using proper tags will give you a better chance of getting an answer. — camickr
– camickr, Commented Dec 1, 2019 at 23:50
The conversion depends strongly on the kind of the URL (remote or local) — vadian
– vadian, Commented Dec 3, 2019 at 12:10

Wassim Ben Hssen · Accepted Answer · 2019-12-03 12:05:57Z

3

to convert url to string use this

var myurl: NSURL
var urlString: String = myurl.absoluteString

hope it helps

answered Dec 3, 2019 at 12:05

Wassim Ben Hssen

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1 Comment

Antonio Abrantes Over a year ago

I have to modify to urlString = (strurl as AnyObject).absoluteString!

Haya Hashmat · Accepted Answer · 2019-12-04 06:01:24Z

3

yes its easy to do.You can try:

var yourURL:NSUL!
var a = yourURL.absoluteString

edited Dec 4, 2019 at 6:01

answered Dec 3, 2019 at 12:26

Haya Hashmat

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1 Comment

Haya Hashmat Over a year ago

have you tried ? let url = URL(string: "zerotoappstore.com/") let urlString = url.absoluteString

devojoyti · Accepted Answer · 2019-12-03 11:46:55Z

1

Doesnt' work, but what is the error?

Try not to force-downcast your optionals when not absolutely necessary. Use if let optional unwrapping or guard Anyway, try this -

if let strurl = url {
    let urlString = strurl.absoluteString 
    print(type(of: urlString))  // should print "String"
}
else {
    // Your url is nil 
}

answered Dec 3, 2019 at 11:46

devojoyti

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1 Comment

Antonio Abrantes Over a year ago

I have to modify to; urlString = (strurl as AnyObject).absoluteString!

aj007 · Accepted Answer · 2020-02-14 06:32:00Z

1

Go through this link Here you can find url to string and string to url

https://www.zerotoappstore.com/swift-url-to-string.html

answered Feb 14, 2020 at 6:32

aj007

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Comments

Nikunj · Accepted Answer · 2019-12-03 12:32:33Z

0

You can convert url to string by using url.absoluteString.

imagens.child("\(self.idImagem).jpg").downloadURL(completion: { (url, erro) in
                        if(erro == nil)
                        {
                            print(url?.absoluteString)
                            let urlString = url.absoluteString
                            self.performSegue(withIdentifier: "selecionarUsuarioSegue", sender: urlString)
                        }else{
                            print(err!);
                        }
                    })

answered Dec 3, 2019 at 12:32

Nikunj

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