PHP / HTML checkbox button [duplicate]

Question

I have a GPA calculator form, and when a user enters their information, I want it to stay populated on the screen.

    E-mail: <input type="text" size="35" name="email" value="<?php echo $email; ?>">
    <span class="error"><?php echo $emailErr; ?></span>
    <br><br>

    <input type="checkbox" name="agree" >
    I agree to the terms and conditions of this website.
    <span class="error"><?php echo $agreeErr; ?></span>
    <br><br>

I have no problem with my other variables, but I cannot get my checkbox to stay on the screen. When the user hits submit, the checkbox will un-check again. How can I make it stay checked on the screen?

Thank you!

Check the checkbox value on server: As I remember, $_POST['agree'] maybe true. When you re-populate to the form, add attribute check=<?= $_POST['agree'] ?> to the checkbox Btw, I dont think this question is relevant to computer-science — Kien Pham
– Kien Pham, Commented Oct 17, 2019 at 4:00

catherinethegreat · Accepted Answer · 2019-10-17 04:08:44Z

0

Through trial and error, I have found a simple solution:

<input type="checkbox" name="agree" 
value="agree" <?php if(isset($_POST['agree'])) echo "checked='checked'";?> 
>I agree to the terms and conditions of this website.
<span class="error"><?php echo $agreeErr; ?></span>

Just in case anyone else gets stuck on this same problem!

answered Oct 17, 2019 at 4:08

catherinethegreat

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