php conditional statement: not equal to operator

Question

I am trying to do the following with wordpress:

"If is NOT page 92, OR page parent is NOT 92."

Here is what I have:

<?php if (!is_page(92) || $post->post_parent !== 92) { echo $foo; } ?>

If I use one or the other as condition, it works; When I add the second condition, it breaks.

Any help would be well appreciated.

Cheers!

have you checked the values of both, to ensure they are not the same value? — Mild Fuzz
– Mild Fuzz, Commented Apr 20, 2011 at 14:43
Just to clarify language ambiguity, you do mean "if either the page is not 92 or if parent is not 92", and not "if neither page nor parent are 92," right? (For the latter you'd need && instead of ||.) — Wiseguy
– Wiseguy, Commented Apr 20, 2011 at 14:55
@Cyclone My intended condition does not filter. (the variable foo, displays on the pages I want to exclude it from) — Michel Joanisse
– Michel Joanisse, Commented Apr 20, 2011 at 14:55

Phoenix · Accepted Answer · 2011-04-20 15:03:36Z

3

Your problem is probably in using || instead of &&.

You want it to echo if you are not on page 92 AND you are not in a subpage of page 92.

Let's say you're on page 92, then your current code does this:

if (false || true)

because 92 is not a parent of page 92. Thus, since one condition is true, it triggers.

If you're on a subpage of 92, then it's the opposite:

if (true || false)

If you're on a page that isn't 92 or a subpage of 92, then you get:

if (true || true)

So, it will always trigger, regardless of what page your on, because || requires only a single true statement for the entire condition to be true.

Hence, change your code to

<?php if (!is_page(92) && $post->post_parent !== 92) { echo $foo; } ?>

Which gives a logical run down like:

Page 92:

if(false && true) //false, won't trigger

Subpage of 92:

if(true && false) //false, won't trigger

Some unrelated page:

if(true && true) //true, will trigger

edited Apr 20, 2011 at 15:03

answered Apr 20, 2011 at 14:58

Phoenix

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2 Comments

Michel Joanisse Over a year ago

ahhhhh, yes. You are right! I forgot that if one condition was met, condition is triggered..

Wiseguy Over a year ago

Oh. That's what I thought I had clarified in the comments above.

Jarrod Nettles · Accepted Answer · 2011-04-20 14:47:04Z

1

You have an additional equals sign in your statement. The operator !== is for boolean checks. Since post_parent will automatically resolve to "true" since it has a value, it will always echo "foo". Change it to the following.

<?php if (!is_page(92) || $post->post_parent != 92) { echo $foo; } ?>

answered Apr 20, 2011 at 14:47

Jarrod Nettles

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4 Comments

Phoenix Over a year ago

Not true. !== is for all data types. Of course, it could be his problem, if $post->post_parent returns a string and not an int, then it wouldn't work.

Jarrod Nettles Over a year ago

Agreed - I forgot that variables with values present will auto-resolve to "true".

Phoenix Over a year ago

No, no, no. !== checks for equivalency and type. "92" !== 92 is true because one is a string and the other is an int. 92 !== 92 is false because they are both ints and equivalent to one another. "92" != 92 is false, because it doesn't check type and will type juggle to see if they are equivalent.

Jarrod Nettles Over a year ago

Then I'm curious as to the behavior of the is_page() function and the returned result from there. It may be what is causing your conditional to fail.

elvenbyte · Accepted Answer · 2011-04-20 14:43:38Z

0

It's only != not !==, only one equal

answered Apr 20, 2011 at 14:43

elvenbyte

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2 Comments

Yoshi Over a year ago

See: php.net/manual/en/language.operators.comparison.php 'Not identical' I don't think this is the problem here.

Phoenix Over a year ago

It can be !== too. !== is the literal type checking one.

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