Does boost::multi_array default initialize its contents?

Question

std::vector<T> foo(100) initialises every element with the default value for T. Does boost::multi_array<T, 2> foo(boost::extents[10][10]) do the same?

Timmmm · Accepted Answer · 2019-07-02 13:46:00Z

1

It does, using std::allocator::construct() by default.

answered Jul 2, 2019 at 13:46

Timmmm

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alfC Over a year ago

That is right, and construct calls new(p) U(); which initializes to zero even for trivial types. I think this choice is a mistake for trivial types for performance and debuggability reasons (it is not possible to detect initialized memory because of this forced initialization).

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