Trying to call a flask function with parameters from html [duplicate]

Question

So Im calling a flask function which takes one parameter check from my html code, im getting the error: TypeError: categories_html() missing 1 required positional argument: 'check'.

Heres my Python code:

app.route('/cat_html', methods=['GET'])
def categories_html(check):
    if session.get('teacher_name'):
        return trav0.gen(check)

    else:
        return redirect('/teachers')

And then here is the html call:

<li class="nav-item">
    <a class="navbar-brand" href="{{ url_for('categories_html', check='sta10') }}" target="_blank" style="color:31708f;">Tasks</a>
</li>

So trav0.gen generates a html, check is simply equal to a number, depending on the number a different html is generated.

Mark · Accepted Answer · 2019-06-27 13:42:59Z

0

It's not 100% clear what you want the url to look like for cat_html.

You can do a couple things.

For a url like /cat_html/sta10 you would write the method like:

@app.route('/cat_html/<check>', methods=['GET'])
def categories_html(check):
    # use check here
    return check

check will be part of the url path.

To pass check as a query parameter with a url like /cat_html/?check=sta10, you don't add it as parameter to the function, you get() it in the function:

@app.route('/cat_html/', methods=['GET'])
def categories_html():
    check = request.args.get('check', '')
    # use check here
    return check

answered Jun 27, 2019 at 13:42

Mark

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