Bash command not found comparing string with variable [duplicate]

Question

I need to compare a variable with a string (how hard can it be)

#!/bin/bash

a=22

if ["$a" == "23"]
then
    echo yes yes
fi

I get

./x: line 5: [22: command not found

I've tried to remove quotes, or use [[...]]. But whatever I do, I get the command not found error. Any suggestions what I do wrong?

Well, that changes the error @Fabio. Now I get: ./x: line 3: local: can only be used in a function ./x: line 5: [: missing ]'` — Jeanluca Scaljeri
– Jeanluca Scaljeri, Commented Jun 22, 2019 at 21:11
Spaces are important delimiters in shell syntax, and adding or removing them will often change the meaning of a command. — Gordon Davisson
– Gordon Davisson, Commented Jun 22, 2019 at 22:08
notice that while the fundamental problem was the spacing, you should use -eq to compare integers instead of ==. Furthermore, == is understood by Bash, but isn't POSIX compliant; use = instead for improved portability. — Benjamin W.
– Benjamin W., Commented Jun 22, 2019 at 22:42

gregory · Accepted Answer · 2019-06-22 21:20:35Z

2

[ "$a" == "22" ] <--- you need a space before the closing backet

answered Jun 22, 2019 at 21:20

gregory

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