Problem with getting client IP address in ASP.NET CORE Web API?

Question

I get server IP Address instead of client IP by using below method in ASP.NET CORE Web API . Please tell me where I'm going wrong. I have used ServerVariables["HTTP_X_FORWARDED_FOR"] in asp mvc before and that has worked correctly.

private string DetectIPAddress(HttpRequest request)
{
    var _IP = "RemoteIp:" + request.HttpContext.Connection.RemoteIpAddress.ToString() + " - LocalIpAddress:" +
                  request.HttpContext.Connection.LocalIpAddress;
    try
    {
        _IP += " IP.AddressFamily:" + Dns.GetHostEntry(Dns.GetHostName()).AddressList[1].ToString();

        _IP += " HostName:" + Dns.GetHostEntry(Dns.GetHostName()).HostName;

    }
    catch (Exception e)
    {

    }

    return _IP;
}

See this doc about forwarded headers: learn.microsoft.com/en-us/aspnet/core/host-and-deploy/… — Tratcher
– Tratcher, Commented Jun 11, 2019 at 14:46

CodingYourLife · Accepted Answer · 2021-04-03 23:30:30Z

6

Getting the client IP sounds easy but in fact I've tried to get the client IP for many hours until I found this gist extension method in @Voodoo's comment that helped me. I want to make it more prominent and therefore create a separate answer. It works with .NET 5 on AWS fargate likely with some kind of load balancer pass-through where RemoteIpAddress alone does not work.

public static class HttpContextExtensions
{
    //https://gist.github.com/jjxtra/3b240b31a1ed3ad783a7dcdb6df12c36

    public static IPAddress GetRemoteIPAddress(this HttpContext context, bool allowForwarded = true)
    {
        if (allowForwarded)
        {
            string header = (context.Request.Headers["CF-Connecting-IP"].FirstOrDefault() ?? context.Request.Headers["X-Forwarded-For"].FirstOrDefault());
            if (IPAddress.TryParse(header, out IPAddress ip))
            {
                return ip;
            }
        }
        return context.Connection.RemoteIpAddress;
    }
}

Use it like this:

var ip = HttpContext.GetRemoteIPAddress().ToString();

answered Apr 3, 2021 at 23:30

CodingYourLife

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1 Comment

Boppity Bop Over a year ago

as usual for SO - the correct answer is the last in the list..

Marian Kosaniak · Accepted Answer · 2021-12-15 19:47:09Z

1

I using this method to get IP in .net core 3.1

    public static string GetIPAddress(HttpContext context)
    {
        if (!string.IsNullOrEmpty(context.Request.Headers["X-Forwarded-For"]))
        {
            return context.Request.Headers["X-Forwarded-For"];
        }
        return context.Connection?.RemoteIpAddress?.ToString();
    }

In Startup.cs add this code

 app.UseForwardedHeaders(new ForwardedHeadersOptions() { ForwardedHeaders = ForwardedHeaders.XForwardedFor | ForwardedHeaders.XForwardedProto | ForwardedHeaders.All });

answered Dec 15, 2021 at 19:47

Marian Kosaniak

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Comments

Voodoo · Accepted Answer · 2019-06-11 05:17:30Z

0

In Asp.Net Core Web API to get Remote Client, IP Address is changed to the previous version of Asp.Net

Asp.Net Core introduced a new library for Http request and response.

Require the following namespace to add.

using Microsoft.AspNetCore.Http.Features;

Once, you added namespace then just need to add following a line of code for capture the Remote Client IP Address.

HttpContext.Features.Get()?.RemoteIpAddress?.ToString();

Note: When you try to run the application from the local system so above line of code return the result "::1" but it will work once you deploy your application somewhere

answered Jun 11, 2019 at 5:17

Voodoo

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4 Comments

bahar.alirezaei Over a year ago

It dose not work.it retuns my server IP. log ipAddress192.168.160.1

Voodoo Over a year ago

Please refer this gist.github.com/jjxtra/3b240b31a1ed3ad783a7dcdb6df12c36

bahar.alirezaei Over a year ago

I also add ForwardedHeadersOptions in statup.cs and it works correctly.Thanks a lot

Tratcher Over a year ago

HttpContext.Connection.RemoteIpAddress and HttpContext.Features.Get<IHttpConnectionFeature>()?.RemoteIpAddress give the same result. The correct answer here is ForwardedHeaders.

Mohammad Komaei · Accepted Answer · 2021-08-17 16:28:30Z

0

Use this line in your action method :

string ipAddress = HttpContext.Connection.RemoteIpAddress?.ToString();

edited Aug 17, 2021 at 16:28

answered Aug 17, 2021 at 16:05

Mohammad Komaei

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