I want to create a code that would generate number of random strings (for eg.10 in this case). I used the code below but the code kept on generating same strings
Input Code
import random
import string
s = string.ascii_lowercase
c = ''.join(random.choice(s) for i in range(8))
for x in range (0,10):
print(c)
Output
ashjkaes
ashjkaes
ashjkaes
ashjkaes
ashjkaes
ashjkaes
ashjkaes
ashjkaes
press any key to continue .....
Please help
What you do now is you generate a random string c then print it 10 times
You should instead place the generation inside the loop to generate a new string every time.
import random
import string
s = string.ascii_lowercase
for i in range(10):
c = ''.join(random.choice(s) for i in range(8))
print(c)
Since Python 3.6, you can use random.choices (see this answer). Example:
import random
import string
sample = "".join(random.choices(string.ascii_lowercase, k=10))
print(sample)
As already noted, you need to have random.choice inside loop, what I want to note, that you could use underscore (_) meaning I do not care for that variable together with for, which in this case would mean:
import random
import string
s = string.ascii_lowercase
for _ in range(10):
c = ''.join(random.choice(s) for _ in range(8))
print(c)
I do not want you to feel obliged to do so, but be aware about such convention exist in Python language.
Try below to achieve result what you want
import random
import string
s = string.ascii_lowercase
for x in range (0,10):
print(''.join(random.choice(s) for i in range(8)))
This will give you random string including numbers, uppercase and lowercase letters.
import string, random
random_string=''
for x in range(8):
if random.choice([1,2]) == 1:
random_string += random_string.join(random.choice(string.ascii_letters))
else:
random_string += random_string.join(random.choice(string.digits))
print(random_string)
random.choicein theforloop to make a new one each time.