How to get a string's hex value with string type in Go

Question

I have a string, byteArray:

byteArray := []byte("Hello, 世界-123..")
fmt.Println(byteArray)

which looks like:

[72 101 108 108 111 44 32 228 184 150 231 149 140 45 49 50 51 46 46]

I need to get byteArray[0] as a string, like "72", but they're byte type.

How do I achieve this?

You are looking for strconv.Itoa or strconv.FormatUint. That's not hex encoding, though. — Peter
– Peter, Commented Apr 24, 2019 at 6:27

Darshan Rivka Whittle · Accepted Answer · 2019-04-24 09:20:34Z

1

byteArray := []byte("Hello, 世界-123..")

for _, v := range byteArray {
    s := strconv.Itoa(int(v))
    fmt.Printf("%T, %v\n", s, s)
}

34.2k7 gold badges97 silver badges114 bronze badges

answered Apr 24, 2019 at 6:41

zzn

2,46518 silver badges30 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Joao Henrique · Accepted Answer · 2019-04-24 06:23:06Z

-2

There you go.

byteArray := []byte("Hello, 世界-123..")
fmt.Println(string(byteArray[0]))

// H

answered Apr 24, 2019 at 6:23

Joao Henrique

5875 silver badges13 bronze badges

``` string(byteArray[0] ``` this will turn byte "72" to string "H"