Hello i am trying to convert 00000000000000000000000000001011 to uint32 in golang using
var v = "00000000000000000000000000001011"
fmt.Printf("%T\n", v)
c := []byte(v)
u := binary.LittleEndian.Uint32(c)
However it is not working.
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1"Not working" means what? Errors? Unexpected results?tadman– tadman2019-02-21 19:06:24 +00:00Commented Feb 21, 2019 at 19:06
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@govind int(0000000000000000000000000000101) should equal uint32(0000000000000000000000000000101) instead got 65Remario– Remario2019-02-21 19:13:50 +00:00Commented Feb 21, 2019 at 19:13
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2 Answers
You can't use encoding/binary for this, as that is to serialize and deserialize the (memory) bytes of different values (e.g. numbers). What you have is the base 2 string representation of the number.
To get its integer value you have to parse it. For that, use strconv.ParseUint():
s := "00000000000000000000000000001011"
u, err := strconv.ParseUint(s, 2, 32)
if err != nil {
panic(err)
}
fmt.Println(u)
This outputs (try it on the Go Playground):
11
Note that strconv.ParseUint() returns a value of type uint64, so if you need uint32, you have to manually convert it, e.g.:
u32 := uint32(u)
There are more options for parsing numbers from strings, for an overview, check Convert string to integer type in Go?
Comments
For example,
package main
import (
"fmt"
"strconv"
)
func main() {
s := "00000000000000000000000000001011"
fmt.Println(s)
u64, err := strconv.ParseUint(s, 2, 32)
u32 := uint32(u64)
if err == nil {
fmt.Println(u32)
}
}
Playground: https://play.golang.org/p/yiicgWsb7B_M
Output:
00000000000000000000000000001011
11
