C# Web API Method Json Serialized

Question

I am doing a C# web Api Method and the Consumer.

Firstly, the method retrieve a class instance and the Consumer call it like this, and parse it to a Class called R

HttpResponseMessage response = client.PostAsJsonAsync(url, param).Result;
R value = await response.Content.ReadAsJsonAsync<R>();

Now, I need to retrieve from my Api, only the class properties it have data. For that reason it parse the class instance to Json, as i asked here, using

 string jsonIgnoreNullValues = JsonConvert.SerializeObject(response, Formatting.Indented, new JsonSerializerSettings
                {
                    NullValueHandling = NullValueHandling.Ignore
                });

My web Method definition is simple

   public IHttpActionResult Newemployee([FromBody] RequestManual items)
    {
         ResponseManual response = Service.Newemployee(items.Datos);
         //Before
          return Ok(response);

          //Now
           string jsonIgnoreNullValues = JsonConvert.SerializeObject(response, Formatting.Indented, new JsonSerializerSettings
                {
                    NullValueHandling = NullValueHandling.Ignore
                });
          return Ok(jsonIgnoreNullValues);
    }

}

.NET automatically Serialize to Json in the response, When i Serialize the response to avoid null properties, the respose is getting serialized twice...

How can avoid this, or how can I read this?

Thanks

Nkosi · Accepted Answer · 2019-02-06 18:17:47Z

2

Configure the formatter at startup. Under the hood Web API is using Json.Net framework, so you will have access to the same serialization settings

WebApiConfig.cs

var jsonFormatter = config.Formatters.JsonFormatter
jsonFormatter.SerializerSettings.NullValueHandling = NullValueHandling.Ignore

That way you can use the original code as before

[HttpPost]
public IHttpActionResult Newemployee([FromBody] RequestManual items) {
    if(ModelState.IsValid) {
        var response = Service.Newemployee(items.Datos);
        return Ok(response);
    }
    return BadRequest(ModelState);
}

answered Feb 6, 2019 at 18:17

Nkosi

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