Convert the hexadecimal string representation of some bytes into a byte array in Java

Question

I am having a hard time trying to convert a String containing the hexadecimal representation of some bytes to its corresponding byte array.

I am getting 32bytes using the following code:

StringBuffer sb = new StringBuffer();
for (int i = 0; i < mdbytes.length; i++) {
    sb.append(Integer.toString((mdbytes[i] & 0xff) + 0x100, 16).substring(1));
}
return sb.toString();

Any idea how to get from the String to the array? In other words, how to do the reverse of the code above.

Thanks.

Bozho · Accepted Answer · 2011-03-24 21:46:06Z

4

I'd try commons-codec byte[] originalBytes = Hex.decodeHex(string.toCharArray()). In fact I would use it also for the encoding part.

answered Mar 24, 2011 at 21:46

Bozho

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Comments

Esko Luontola · Accepted Answer · 2011-03-24 21:52:43Z

1

You can use the Integer.parseInt(String s, int radix) method to convert the hexadecimal representation back to an integer, which you can then cast into a byte. Use that to process the string two characters at a time.

edited Mar 24, 2011 at 21:52

answered Mar 24, 2011 at 21:46

Esko Luontola

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Comments

katsharp · Accepted Answer · 2011-03-24 21:37:34Z

-1

Use the

String.getBytes();

method

answered Mar 24, 2011 at 21:37

katsharp

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1 Comment

Ankit Singh Over a year ago

this will give byte array conversion of the already byte representation of the String which will be very different from the original intended Hex.

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