Properly create CURL calls using loop in bash script

Question

I need to call an API where I increment the user ID every time, I have the following in the bash script, but keep getting a Unexpected token ' in JSON at position 2 error. What am I doing wrong?

for ((i=1;i<=5;i++)); do
    curl -X POST --header 'Content-Type: application/json' -d "{ 'id': 'person'$i, 'name': 
    'person', 'info': {} }" 'http://localhost:9999/add'

learn to debug your problems with simple echo curl -X ...... localhost:9999/add" Good luck. — shellter
– shellter, Commented Nov 16, 2018 at 23:23

OneMoreQuestion · Accepted Answer · 2018-11-16 21:18:23Z

2

It is a quoting issue. It is standard for JSON to have double quotes, try this

for ((i=1;i<=5;i++)); do
  echo "Adding person"$i
  curl -X POST --header 'Content-Type: application/json' --header 
  'Accept: application/json' --user 'admin' -d '{ "id": "person'$i'", "name": 
  "person", "info": {} }" 'http://localhost:9999/add'
done

answered Nov 16, 2018 at 21:18

OneMoreQuestion

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dalmo.santos · Accepted Answer · 2018-11-16 20:48:40Z

0

You can use jq, to edit json by shellscript. See this link.

answered Nov 16, 2018 at 20:48

dalmo.santos

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