Remove element from Array of Arrays

Question

I have a array of arrays like the following:

myArray = [
  ["ooooh", "that"],
  ["dog ", "of"],
  ["mine", "word...."]
]

I now wish to delete the array item: ["ooooh", "that"]

Assuming that I know element 0 is "ooooh" and element 1 is "that", but i do not know the element's position within the enclosing array, can this be achieved efficiently?

The general responses from my research seem to be saying delete myArray['1'], or know the number of the element in the array- in my case in need both element 0 & 1 to match for removal.

In pseudo code i would like:

myArray.destroy(["ooooh", "that"])

How can this be achieved?

myList.splice(myList.findIndex(e => e[0] === "ooooh" && e[1] === "that"), 1); — ASDFGerte
– ASDFGerte, Commented Jul 3, 2018 at 15:33
Can you assume that your delete array will be identical to the one being deleted? — Alex
– Alex, Commented Jul 3, 2018 at 15:33
Possible duplicate of javascript - remove array element on condition — bvrakvs
– bvrakvs, Commented Jul 3, 2018 at 15:35
A note towards my comment: if there is the possibility the element does not exist, you need to add additional code. findIndex will return -1 if it does not exist, and splice will interpret that as splice(myList.length - 1, 1). — ASDFGerte
– ASDFGerte, Commented Jul 3, 2018 at 15:42
@Pitto if you tag PM 77-1 you might get a response from him (seems like he knows the answer ) — Preston
– Preston, Commented Jul 5, 2018 at 13:43

Gerardo BLANCO · Accepted Answer · 2018-07-03 15:35:59Z

3

You can use splice to remove an item out of the list.

myList.splice(
   myList.findIndex( item => 
     item[0] == "ooooh" && item[1] == "that"
   ), 
1);

Hope this helps :>

myList = [
["ooooh", "that"],
["dog ", "of"],
["mine", "word...."]];

myList.splice(myList.findIndex(item => item[0] == "ooooh" && item[1] == "that"), 1);

console.log(myList)

answered Jul 3, 2018 at 15:35

Gerardo BLANCO

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Comments

Luis felipe De jesus Munoz · Accepted Answer · 2018-07-03 15:34:08Z

2

Just filter your array

var myList = [
["ooooh", "that"],
["dog ", "of"],
["mine", "word...."]
]

deleteFromList = (val, list) => list.filter(a=>JSON.stringify(a)!=JSON.stringify(val))

console.log(
  deleteFromList(["ooooh", "that"], myList)
)

/* Same as */

myList = myList.filter(a=>JSON.stringify(a)!=JSON.stringify(["ooooh", "that"]))

console.log(myList)

answered Jul 3, 2018 at 15:34

Luis felipe De jesus Munoz

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Comments

baao · Accepted Answer · 2018-07-03 15:39:30Z

2

You can use filter and every together to have it flexible.

const myList = [
  ["ooooh", "that"],
  ["dog ", "of"],
  ["mine", "word...."]
];

const toDelete = ["ooooh", "that"];

const res = myList.filter(e => ! toDelete.every(x => e.includes(x)));
console.log(res);

answered Jul 3, 2018 at 15:39

baao

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Comments

Nelson Teixeira · Accepted Answer · 2018-07-03 15:45:03Z

2

Well there are several ways of doing this as the other answers pointed out, but I think the simplest way is to use filter. Like this::

myList = [
    ["ooooh", "that"],
    ["dog ", "of"],
    ["mine", "word"]
];
    
myList = myList.filter((element)=>
    //filter condition 
    (!
       ((element[0] == 'ooooh') && (element[1] == 'that'))
    )
);

console.log(myList)

edited Jul 3, 2018 at 15:45

answered Jul 3, 2018 at 15:36

Nelson Teixeira

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Comments

Vanojx1 · Accepted Answer · 2018-07-03 15:35:13Z

1

You can use the filter function comparing arrays as strings

myList = [
  ["ooooh", "that"],
  ["dog ", "of"],
  ["mine", "word...."]
];

let findMe = ["ooooh", "that"]

myList = myList.filter((curr) => curr.join() !== findMe.join())

console.log(myList)

answered Jul 3, 2018 at 15:35

Vanojx1

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Comments

Alex · Accepted Answer · 2018-07-03 15:39:21Z

0

I'm late to the party but here is my input:

let myList = [
  ["ooooh", "that"],
  ["dog ", "of"],
  ["mine", "word...."]
];

Array.prototype.destroy = function(array) {
  this.forEach((el, i) => {
    if (JSON.stringify(el) === JSON.stringify(array)) {
      this.splice(i, 1);
    }
  });
}

console.log(myList);

myList.destroy(["ooooh", "that"]);

console.log(myList);

answered Jul 3, 2018 at 15:39

Alex

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Comments

Pitto · Accepted Answer · 2018-07-06 11:22:23Z

0

You can also use pop to remove an item out of your array.
Here's its documentation.

myArray = [
["ooooh", "that"],
["dog ", "of"],
["mine", "word..."]
]

console.log("Original Array:");
console.log(myArray);

/**
 * Removes one array from an array of arrays 
 *
 * @param  {String} myArray       - The original array of arrays
 * @param  {String} arrayToRemove - The array that will be removed from myArray
 */
function destroy(myArray, arrayToRemove) {
        arrayIndexToBeRemoved = myArray.findIndex(item => item[0] == arrayToRemove[0] && item[1] == arrayToRemove[1]);
        if (arrayIndexToBeRemoved != -1){
            removedArray = myArray.pop(arrayIndexToBeRemoved);
            console.log("Removed: " + removedArray);
        } else {
            console.log("Couldn't find: " + arrayToRemove + " in: " + myArray);
        }
}

destroy(myArray, ["mine", "word..."]);

console.log("Final Array:");
console.log(myArray);

edited Jul 6, 2018 at 11:22

answered Jul 3, 2018 at 15:31

Pitto

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1 Comment

Preston Over a year ago

thanks for the response, and i'm not the downvoter, but this needs to be for a list of lists, and pop would show the last element pushed to the list no?

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