Conditional access of array elements

Question

I have a data vector data = [x for x in range(0,999)] what I want to do is that to, access elements in data according to a given value e.g if value=10 access 0th index of data and if value=20 access 1st index of data. It is supoused to be something like this:

def get_data(value):
if value ==10:
    return data[0]
elif value == 20:
    return data[1]
elif value ==30:
    return data[2]

But in reality, i will have really big data and I cannot keep putting elif statements. Is there any efficient way of doing this?

You can check there, may help you.. :)

AntoineLB
– AntoineLB

2018-05-14 09:49:20 +00:00
Commented May 14, 2018 at 9:49 — AntoineLB
– AntoineLB, Commented May 14, 2018 at 9:49

Mihai Alexandru-Ionut · Accepted Answer · 2018-05-14 09:47:57Z

1

One approach could be dividing the value to 10 and then just substract 1 from result.

return data[value//10 - 1]

answered May 14, 2018 at 9:47

Mihai Alexandru-Ionut

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Comments

Amardeep Anand · Accepted Answer · 2018-05-14 10:07:41Z

1

You can use a dictionary to solve your problem.

def get_data(value):
     return {
         10: data[0],
         20: data[1],
         30: data[2]
     }.get(value, data[3])   #data[3] will be the default value.

answered May 14, 2018 at 10:07

Amardeep Anand

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1 Comment

Salman Shaukat Over a year ago

But my array [10,20,30,.....] is really large. it is not possible to assign each value to dictionary manually

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