Python array elements in if statement

Question

I have some array with integers, and for loop. I am trying to test if some specific elements in array is bigger or smaller that some integer. This code explain it better:

array = [1,2,3,4,5]
for i in range(5):
    if array[i] >= 3:
        print(sometext)
    else:
        print(othertext)

But i got an ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()

SOLUTION: I did indent it properly. This above is just simplification(some stupid example) of my code. I found where the error is. It is because I initialized array with numpy as

a = numpy.empty(5) and not like this:

a = [0 for i in range(5)]

Thank you everybody for your help

This link might be useful to you, possible duplicate? stackoverflow.com/questions/10062954/… — Wool
– Wool, Commented Apr 24, 2018 at 16:07
This might seem pedantic, but that isn't an array, that is a list. However, your error message seems to come from numpy. You should provide a minimal reproducible example, although your question is almost certainly a duplicate — juanpa.arrivillaga
– juanpa.arrivillaga, Commented Apr 24, 2018 at 16:07

Gabriel · Accepted Answer · 2018-04-24 16:10:58Z

4

You should iterate over the array itself:

array = [1, 2, 3, 4, 5]

for item in array:
    if item >= 3:
        print("yes")
    else:
        print("no")

edited Apr 24, 2018 at 16:10

answered Apr 24, 2018 at 16:07

Gabriel

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Anand.G.T · Accepted Answer · 2018-04-24 16:11:53Z

2

It worked for me with proper intendations:

>>> array = [1,2,3,4,5]
>>> for i in range(5):
...     if array[i] >= 3:
...             print("Yes")
...     else:
...             print("No")
...

answered Apr 24, 2018 at 16:11

Anand.G.T

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Comments

Chandra Shekhar · Accepted Answer · 2018-04-24 16:16:06Z

0

The Error that you are getting is basically due to INDENTATION . Python strictly follows indentation , meaning that it will only execute codes written in that specific Block . Refer Python Indentation Rule for more details. Thank You. Happy Coding Ahead.

answered Apr 24, 2018 at 16:16

Chandra Shekhar

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1 Comment

Falco Peregrinus Over a year ago

I did indent it properly in my code, but sorry, not here in post.

tbobm · Accepted Answer · 2018-04-26 10:26:09Z

0

This isn't really the most pythoninc way of doing what you're describing.

array = [1,2,3,4,5]
for element in array:
    if element >= 3:
        print("Yes")
    else:
        print("No")

Reference: https://wiki.python.org/moin/ForLoop

edited Apr 26, 2018 at 10:26

answered Apr 24, 2018 at 16:09

tbobm

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Finn Ledlin · Accepted Answer · 2024-05-06 11:56:05Z

0

I gave this a go

array = [1,2,3,4,5]

x1 = (array[0])
x2= (array[1])
x3= (array[2])
x4= (array[3])
x5= (array[4])


if x1 <= x2:
  print("very good")
else:
  print("also good")

how's that?

answered May 6, 2024 at 11:56

Finn Ledlin

1

1 Comment

Community Over a year ago

As it’s currently written, your answer is unclear. Please edit to add additional details that will help others understand how this addresses the question asked. You can find more information on how to write good answers in the help center.

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