In my code, I need to call a sub-module, and in the sub-module I need to require a file that only has a relative path. So I need to join the 'current main' code path to the relative path.
I tried to use:
var conf = require(path.resolve(__dirname + ConfigPath));
But __dirname will get me the current sub-module path. What I need here is the main code path.
Can anyone please help here? many thanks!
(Node.JS context only)
For your "sub-module" (the generic approach): use __dirname
For your "parent-module" (or even the topmost / main module): use process.mainModule
See further details @ https://nodejs.org/api/process.html#process_process_mainmodule
This is how you can further processs the mainModule information.
var fnArr = (process.mainModule.filename).split('/');
var mmFilename = fnArr[fnArr.length -1];
