I have an array that contains string elements:
farm = np.array(garden)
leads to this:
[['F' 'F' 'W' 'W']
['F' '_' '_' 'W']
['G' '_' '_' 'J']
['G' 'G' 'J' 'J']]
I want to count how many times lets say 'F' appears, is there a simple way to do this? This is a small version of the bigger array that I will be working on
EDIT: Lists have a count method. So your new and improved pythonic code is
D= sum([i.count("F") for i in listX])
Well you can make a function, that Checks if the parameter passed to it is in the array. You can even use list comprehensions. For example
F = sum([sum([1 for i in j if i=="f"]) for j in listX])
Michael's solution is the most "pythonic", but I wanted to offer an alternative solution using simpler constructs, in case you're just learning:
lst = []
lst.append(['F', 'F', 'W', 'W'])
lst.append(['F', '_', '_', 'W'])
lst.append(['G', '_', '_', 'J'])
lst.append(['G', 'G', 'J', 'J'])
numFs = 0
# Look at each sublist
for sublist in lst:
# Look at each element within the sublist
for s in sublist:
# If the element is an 'F', add 1 to the number of Fs
if s == 'F':
numFs += 1
print(numFs)
You could also try to reduce and join the elements of the arrays into a string and then count, like so:
from functools import reduce
a = [['F' 'F' 'W' 'W'], ['F' '_' '_' 'W'], ['G' '_' '_' 'J'], ['G' 'G' 'J' 'J']]
c = ''.join(reduce(list.__add__, a)).count('F')
print(c)
When executed, this code prints:
3
collections.Counter()returns a dictionary of unique elements and their counts in a list.