Javascript get date in format [duplicate]

Question

I want to get today's date in the format of mm-dd-yyyy

I am using var currentDate = new Date(); document.write(currentDate);

I can't figure out how to format it.

I saw the examples var currentTime = new Date(YY, mm, dd); and currentTime.format("mm/dd/YY");

Both of which don't work

I finally got a properly formatted date using

var today = new Date();
var dd = today.getDate();
var mm = today.getMonth()+1;//January is 0!`

var yyyy = today.getFullYear();
if(dd<10){dd='0'+dd}
if(mm<10){mm='0'+mm}
var today = mm+'/'+dd+'/'+yyyy;
document.write(today);'`

This seems very complex for such a simple task.

Is there a better way to get today's date in dd/mm/yyyy?

I'd do it manually var d = new Date(); var s = new String(); s = (d.getHours()+"-"+d.getMinutes()+"-"+d.getSeconds()+" "+d.getDate()+"-"+d.getMonth()+"-"+d.getFullYear()).toString();. Reference: w3schools.com/jsref/jsref_obj_date.asp — Nav
– Nav, Commented Feb 1, 2015 at 4:53

Ateş Göral · Accepted Answer · 2011-02-08 06:22:48Z

24

Unfortunately there is no better way, but instead of reinventing the wheel, you could use a library to deal with parsing and formatting dates: Datejs

<plug class="shameless">

Or, if you find format specifiers ugly and hard to decipher, here's a concise formatting implementation that allows you to use human-readable format specifiers (namely, the Date instance getters themselves):

date.format("{Month:2}-{Date:2}-{FullYear}"); // mm-dd-yyyy

</plug>

edited Feb 8, 2011 at 6:22

answered Feb 8, 2011 at 3:32

Ateş Göral

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2 Comments

Elliot Bonneville Over a year ago

Nice library, came in handy.

g5thomas Over a year ago

Another useful javascript library is momentjs. momentjs.com You can format the date as follow. moment().format('MM-DD-YYYY')

mrded · Accepted Answer · 2015-03-28 23:38:48Z

19

var today = new Date();

var strDate = 'Y-m-d'
  .replace('Y', today.getFullYear())
  .replace('m', today.getMonth()+1)
  .replace('d', today.getDate());

answered Mar 28, 2015 at 23:38

mrded

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Comments

Victor · Accepted Answer · 2011-02-08 03:29:55Z

4

Simple answer is no. Thats the only way to do it that I know of. You can probably wrap into a function that you can reuse many times.

answered Feb 8, 2011 at 3:29

Victor

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1 Comment

Samuel Meddows Over a year ago

thought that may be the case. Thanks mate

Bao Le · Accepted Answer · 2013-02-19 03:38:58Z

1

date.js is what you need. For example, snippet below is to convert a date to string as Java style

new Date().toString('M/d/yyyy')

edited Feb 19, 2013 at 3:38

answered Oct 8, 2012 at 16:11

Bao Le

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Comments

Widada · Accepted Answer · 2014-12-18 01:30:53Z

1

function dateNow(splinter){
  var set = new Date(); 
  var getDate = set.getDate().toString();
  if (getDate.length == 1){ //example if 1 change to 01
   getDate = "0"+getDate;
  }
  var getMonth = (set.getMonth()+1).toString();
  if (getMonth.length == 1){
   getMonth = "0"+getMonth;
  }
  var getYear = set.getFullYear().toString();
  var dateNow = getMonth +splinter+ getDate +splinter+ getYear; //today
  return dateNow;
}

format this function is mm dd yyyy and the dividing you can choice and replace if you want... for example dateNow("/") you will get 12/12/2014

answered Dec 18, 2014 at 1:30

Widada

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Comments

RichardTheKiwi · Accepted Answer · 2011-02-08 03:33:00Z

0

There is nothing built in, but consider using this if you are already using jQuery (and if not, then you should consider that as well!)

http://plugins.jquery.com/project/jquery-dateFormat

answered Feb 8, 2011 at 3:33

RichardTheKiwi

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Comments

WantToDo · Accepted Answer · 2016-04-10 11:34:25Z

-3

(new Date()).format("MM-dd-yyyy")

N.B. month is "MM" not "mm"

answered Apr 10, 2016 at 11:34

WantToDo

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1 Comment

Suever Over a year ago

Your description is not clear. Also, there are a lot of really good answers to this question already. Does your answer contribute anything? If so, please elaborate in your answer.

Porthos · Accepted Answer · 2014-01-08 13:04:19Z

-4

function appendZeros(value,digits){
    var c= 1;
    initValue = value;
    for(i=0;i<digits-1;i++){
        c = c*10;
        if( initValue < c ){
            value = '0' + value;
        }
    }
    return value;
}

answered Jan 8, 2014 at 13:04

Porthos

1

1 Comment

Matt Murphy Over a year ago

Perhaps this was meant for another question?

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