How to write a regex to validate a specific URL format?

Question

My URL will look something like this :

"/eshop/products/SMART+TV+SAMSUNG+UE55H6500SLXXH+3D/productDetail/ger_20295028/"

Where product names can keep changing here SMART+TV+SAMSUNG+UE55H6500SLXXH+3D and product id here ger_20295028. I tried writing a regex which is wrong.

How can I correct it for the above URL?

Regex:

.*/products/[^/]*?/productDetail/[^/]*?/([^/].*?)/[^/]*?/([^/]*)(/.*?)*$

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– Momin, Commented Mar 14, 2018 at 9:43

Lance Toth · Accepted Answer · 2018-03-14 09:39:52Z

1

You use ? (single character) instead of * (any number) and you also have much more parts at the end than the example you've given. Try something like this

.*/products/[^/]*/productDetail/[^/]*/

answered Mar 14, 2018 at 9:39

Lance Toth

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3 Comments

O.O.Balance Over a year ago

Note that this allows for parts of the URL to be empty, eg /products//productDetail//

Geek Over a year ago

This regex is working fine but I don't want that part to be empty , how can i do that?

Lance Toth Over a year ago

Change [^/]* to [^/]+ as others have suggested

O.O.Balance · Accepted Answer · 2018-03-14 09:42:27Z

0

You should read up on quantifiers (the ? means once or zero times, you are confusing it with *). This regex might work for you:

/^.*\/products\/[^\/]+\/productDetail\/[^\/]+\/$/

Try it online here.

answered Mar 14, 2018 at 9:42

O.O.Balance

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4 Comments

Geek Over a year ago

No , it did not get match

O.O.Balance Over a year ago

@Geek you didn't specify what language you are using to match, but try this: ^.*/products/[^/]+/productDetail/[^/]+/$ instead.

Geek Over a year ago

I am using JAVA

O.O.Balance Over a year ago

"^.*/products/[^/]+/productDetail/[^/]+/$" works fine in Java.

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