How to open a list of urls on new tabs in Selenium + Python?

Question

Code snippet:

import selenium
from selenium import webdriver

driver = webdriver.Chrome()
urls =['fb.com','instgram.com' , 'youtube.com']
for url in urls:
    driver.get(url)
driver.close()

The problem is that it opens the new link on top of the previous one. I want each site to open on a new tab.

Mangohero1 · Accepted Answer · 2018-01-16 01:42:40Z

5

Open the first URL then for the rest, use target: _blank to open each URL in a new tab:

driver.get(urls[0])
for url in urls[1:]:
    driver.execute_script('window.open("{}", "_blank");'.format(url))

And voila, you should have three tabs with three different URLs.

Note about your URLs: These are invalid. Make sure they each have http or https in front of them. And you've accidentally wrote instgram instead of instagram. :P

answered Jan 16, 2018 at 1:42

Mangohero1

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2 Comments

Volatil3 Over a year ago

Is there any advantage in terms of memory while using this?

Mangohero1 Over a year ago

Not to my knowledge, although I'm not so familiar with the memory aspects

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