Delete parameter from URL with swift

Use URLComponents to separate the different URL parts, manipulate them and then extract the new url:

var components = URLComponents(string: "myapp://jhb/test/deeplink/url?id=4567")!
components.query = nil
print(components.url!)

myapp://jhb/test/deeplink/url

A convenient extension on URL

private extension URL {
    var removingQueries: URL {
        if var components = URLComponents(string: absoluteString) {
            components.query = nil
            return components.url ?? self
        } else {
            return self
        }
    }
}

can I achieve that? convert the url to a string? Regex?

When working with URLs, it would be better to treat it as URLComponent:

A structure that parses URLs into and constructs URLs from their constituent parts.

therefore, referring to URLComponent what are you asking is to remove the the query subcomponent from the url:

if var components = URLComponents(string: "myapp://jhb/test/deeplink/url?id=4567") {
    components.query = nil
    
    print(components) // myapp://jhb/test/deeplink/url
}

Note that query is an optional string, which means it could be nil (as mentioned in the code snippet, which should leads to your desired output).

You can do like this

let values = utl?.components(separatedBy: "?")[0]

It will break the string with ? and return the array. The first object of values give you your resultant string.

You can get each URL component separated from URl using

print("\(url.host!)") //Domain name
print("\(url.path)") // Path
print("\(url.query)") // query string