Ansible : pass a variable in a json_query filter

Question

I need to pass a variable in a json_query filter.

This example, with a fixed string, is working correctly (string=tutu) :

- set_fact:
 my_value_exist: "{{ my_json.json | json_query('contains(component.name,`tutu`)')}}"

But i need to pass a variable , instead of tutu

- set_fact:
 my_value_exist: "{{ my_json.json | json_query('contains(component.name,`{{my_var}}`)')}}"

{{my_var}} is a string retreived in a previous step

Do you have the correct syntax, so that the variable {{my_var}} could be passed correctly in parameter ?

Thanks for your help.

Regards,

can you try this: my_value_exist: "{{ my_json.json | json_query('contains(component.name,my_var)')}}" — Arbab Nazar
– Arbab Nazar, Commented Sep 4, 2017 at 15:05
the value exist in the json, but with this syntax the returned value is equal to false. my_value_exit should return true — dbo
– dbo, Commented Sep 4, 2017 at 15:27

Konstantin Suvorov · Accepted Answer · 2017-09-05 06:51:59Z

11

Use helper variable for a task:

- set_fact:
    my_value_exist: "{{ my_json.json | json_query(qry) }}"
  vars:
    qry: 'contains(component.name,`{{my_var}}`'

answered Sep 5, 2017 at 6:51

Konstantin Suvorov

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4 Comments

dbo Over a year ago

I found a solution with this task :

dbo Over a year ago

- name: Does my value exists debug: var=item with_items: "{{ my_json.json | json_query(my_query)}}" vars: my_query: "contains(component.name,{{ my_var | to_json | replace ('\"',\"'\")}})" register: my_value_exist

Konstantin Suvorov Over a year ago

Post it as separate answer, please. But it's an overkill in my opinion.

Jai Over a year ago

helped me when trying to use a variable with json_query. thank you.

gardar · Accepted Answer · 2020-12-02 19:06:23Z

0

If you would like to avoid using a helper var you can use the second var directly by wrapping it in escaped double quotes ( \" ) between plus characters ( + ) like this:

- set_fact:
    my_value_exist: "{{ my_json.json | json_query('contains(component.name,`\" + my_var + \"`)') }}"

I know that this is a old question but it might help someone since this is the top result on the subject on google.

answered Dec 2, 2020 at 19:06

gardar

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