super() will find the next method in the MRO sequence. This means that only one of the __init__ methods in your base classes is going to be called.
You can inspect the MRO (the Method Resolution Order) by looking at the __mro__ attribute of a class:
>>> D.__mro__
(<class '__main__.D'>, <class '__main__.B'>, <class '__main__.C'>, <class 'object'>)
so from D, the next class is B, followed by C and object. From D.__init__(), the super().__init__() expression will only call B.__init__(), and then because C.__init__() is never called, self.c is not set either.
You'll have to add more super() calls to your class implementations; it is safe to call object.__init__() with no arguments, so just use them everywhere here:
class B():
def __init__(self):
print("__init__ of B called")
super().__init__()
self.b = "B"
class C():
def __init__(self):
print("__init__ of C called")
super().__init__()
self.c = "C"
class D(B, C):
def __init__(self):
print("__init__ of D called")
super().__init__()
def output(self):
print(self.b, self.c)
Now B.__init__ will invoke C.__init__, and C.__init__ will call object.__init__, and calling D().output() works:
>>> d = D()
__init__ of D called
__init__ of B called
__init__ of C called
>>> d.output()
B C