Regex - match a string without having spaces

Question

Building an regular expression that will reject an input string which contain spaces.

I have a following expression, but its not working as well;

^[a-zA-Z0-9!@#*()+{}[\\];:,|\/\\\\_\S-]+$

Valid case

String123/test //string without space

Invalid case

String123/ test // contains space in between string 

String 123/test // contains space in between string 

 String123/test  // contains leading\trailing space

i.e; I have to white list strings which does not contain any spaces.

Is it only the space you want to reject or there is another characters? — Niitaku
– Niitaku, Commented Feb 10, 2017 at 9:18
console.log(!(/\s/.test('this is'))); This would be the case — Rahul
– Rahul, Commented Feb 10, 2017 at 9:20

Wiktor Stribiżew · Accepted Answer · 2020-12-07 16:54:16Z

19

You may use \S

\S matches any non white space character

Regex

/^\S+$/

Example

function CheckValid(str){
   re = /^\S+$/
   return re.test(str)
 }


console.log(CheckValid("sasa sasa"))
console.log(CheckValid("sasa/sasa"))                      
console.log(CheckValid("sas&2a/sasa"))

edited Dec 7, 2020 at 16:54

Wiktor Stribiżew

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answered Feb 10, 2017 at 9:20

Sarath Sadasivan Pillai

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2 Comments

Sarath Sadasivan Pillai Over a year ago

@Justin please accept the answer if it solved the problem

Дмитро Олександрович Over a year ago

In Sublime Text it'll be (^\S+$)

Daniel Verejan · Accepted Answer · 2017-02-10 09:28:36Z

1

I suppose that you'll be using .test method on regex, /\s/g this one should do the job, it will return true if there's any space in the string. ex: /\s/g.test("String123/test") this will return false which means that the string is valid /\s/g.test("String123 /test) this will return true which means that the string is not valid

answered Feb 10, 2017 at 9:28

Daniel Verejan

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