Remove a specific value from array in each loop - jQuery

Question

I want to be able to remove values from an array which contain the value round.

An example array submitted could be [team1, team2, round3, round5, team3, round6]

I have this code which is meant to loop through the array and remove an element from the array if it contains round using search

function modifyFilterConfig(idStr, target) {
$.each(idStr, function(i, value){
    console.log("The index of this value is: " + i);
    console.log("The value is: " + value);
    console.log("The value match is: " + value.search(target));
    if(value.search(target) == 0) {
        // IF THE ARRAY CONTAINS A ROUND REMOVED IT FROM THE ARRAY
        // i - 1 is the current index of the array (i.e. the ROUND filter(s))
        idStr = idStr.splice(i - 1, 1);
    }
    i = i++;
});
console.log("Return value:");
console.log(idStr);
return idStr;
}

At the moment the results I get are the last team in the array for example team6 but my desired result is [team2, team3, team6]

Finally, I want the function to return an array as well so I use it the array again in my wider code.

console.log("IDS before processing: " + ids); var ids = modifyFilterConfig(ids, "round"); console.log("IDS after processing: " + ids);

Richard Hamilton · Accepted Answer · 2017-01-31 16:57:31Z

1

Use the filter function and use the RegExp test method.

var arr = ["team1", "team2", "round3", "round5", "team3", "round6"]
arr = arr.filter(e => !/round/.test(e));
console.log(arr);

answered Jan 31, 2017 at 16:57

Richard Hamilton

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2 Comments

WebDevDanno Over a year ago

Smashed it Richard! What is browser compatibility like for such a function?

Richard Hamilton Over a year ago

It should be functional in most browsers if I remember correctly

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