Python/Regex - Replace by pattern only at the end of string

Question

I need to replace every parenthesis at the end of a string. I use this code:

a = '1 (FR) Product (IT, DE, ES)'
b = re.sub(r' \((.*?)\)',r'', a)

But this will replace every parenthesis in my string. How do I tell python to replace it only if the pattern is at the end of the string?

niemmi · Accepted Answer · 2016-12-05 14:00:49Z

2

Capture everything but ( before ) and end of string identifier $:

>>> import re
>>> a = '1 (FR) Product (IT, DE, ES)'
>>> re.sub(r'\(([^(]*\))$', '', a)
'1 (FR) Product '

answered Dec 5, 2016 at 14:00

niemmi

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Comments

Rex D · Accepted Answer · 2016-12-05 15:45:18Z

0

if a[-1] == ")" a = a[:-2] will work

answered Dec 5, 2016 at 15:45

Rex D

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