Input: blah.(2/2)
Desired Output: blah
Input can be "blah.(n/n)" where n can be any single digit number.
How do I use regex to achieve "blah"? This is the regex I currently have which doesn't work:
m = re.sub('[.[0-9] /\ [0-9]]{6}$', '', m)
4 Answers
You need to use regex \.\(\d/\d\)$
>>> import re
>>> str = "blah.(2/2)"
>>> re.sub(r'\.\(\d/\d\)$', '',str)
'blah'
Comments
Just do this since you will always be looking to split around the .
s = "stuff.(asdfasdfasdf)"
m = s.split('.')[0]
6 Comments
rebeling
blah. blah. boom. What about '.'.join(s.split('.')[:-1])
idjaw
I don't see that it is necessary to convert your list to a string when you can simply just extract the string you need after your split right away.
rebeling
blah. blah. boom.(4/2) What do you expect to get?
idjaw
Apologies, I don't understand what you are asking.
rebeling
No worries. But sometimes there is another dot. Try print "blah. blah. boom.(4/2)".split('.')[0]
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I really like the simplicity of the @idjaw's approach. If you were to solve it with regular expressions:
In [1]: import re
In [2]: s = "blah.(2/2)"
In [3]: re.sub(r"\.\(\d/\d\)$", "", s)
Out[3]: 'blah'
Here, \.\(\d/\d\)$ would match a single dot followed by an opening parenthesis, followed by a single digit, followed by a slash, followed by a single digit, followed by a closing parenthesis at the end of a string.
Comments
Just match what you do not want and remove it. In this case, non letters at the end of the string:
>>> re.sub(r'[^a-zA-Z]+$', '', "blah.(1/2)")
'blah'
.