Extract array key into NEW variable

Question

I have an array where there is a key and a value. I generate it by cycling through an image folder:

$images = array(); 
foreach (glob("images/myimages/*.{png,jpg,jpeg,JPG}", GLOB_BRACE) as $filename) {  
    $images[$filename] = filemtime($filename); 
}

arsort($images); 

$newest = array_slice($images, 0, 5);

This gives me the following array:

images/myimages/image1.jpg => 1472497034
images/myimages/IMG_02.JPG => 2347389498
images/myimages/DSC_0066.png => 7837392948
images/myimages/fred_bloggs.jpg => 1472497034
images/myimages/IMG4532.JPG => 2347389498

I want to extract each key from the $newest array into a new variable so image1.jpg becomes $var1, IMG_02.JPG becomes $var2 etc.

I have 2 problems. First, the filename needs the "images/myimages/" pathname stripping from it (and a check whether files exist in that folder). Second, I can't see how to extract the 5 keys into those 5 new variables. All the examples I see extract the key into a variable of the same name such as here http://php.net/manual/en/function.extract.php

How can I achieve this?

Thanks in advance.

Why extract to vars? Just use $newest = array_keys($newest); and then echo $newest[0]; etc... Or loop thru it. Also see basename(). — AbraCadaver
– AbraCadaver, Commented Sep 26, 2016 at 19:30
You almost never want variables like $var1, $var2, etc. Whenever you're doing that, you should just use an array. — Barmar
– Barmar, Commented Sep 26, 2016 at 19:31
As said in the previous comments, better use an array than $varX, but FYI, you can have a look at php.net/manual/fr/function.list.php — olibiaz
– olibiaz, Commented Sep 26, 2016 at 19:35
@AbraCadaver - Nice answer that simplifies what I want to achieve. — Sara44
– Sara44, Commented Sep 27, 2016 at 16:51

Jonathan M. · Accepted Answer · 2016-09-26 19:39:53Z

2

Really I dont understand why you need that. But you could do something like this:

$prefix = 'var'; $count = 0;
foreach($newest as $key => $value) {
   $count++;
   ${$prefix.$count} = $key;
}

echo $var1; // 'images/myimages/image1.jpg'

answered Sep 26, 2016 at 19:39

Jonathan M.

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AbraCadaver · Accepted Answer · 2016-09-27 17:48:30Z

0

You will be better off just using an array:

$newest = array_keys($newest);

Then access 0-4:

echo $newest[0];

To get just the filename:

$newest = array_map('basename', $newest);

Or you can just use basename() when creating your original array.

answered Sep 27, 2016 at 17:48

AbraCadaver

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