Converting found array keys into an array

Question

I have this array

$array = array(
    "one" => "bar",
    "two"    => "21",
    "three"    => "22",
    "four"    => "25",
    "five" => array(
         "xxxxxxxxxxxxxxxxxx" => array(
             "ar1" => "food",
             "ar2" => "dr",
             "ar3" => "ch",
             "ar4" => "ju"
         ),
        "yyyyyyyyyyyyyyyyyyyy" => array(
             "ar1" => "food",
             "ar2" => "dr",
             "ar3" => "ch",
             "ar4" => "ju"
         )),
    "six" => "et",
    "seven" => "op",
    "eight" => "hjs",
    "nine" => array(
         "1" => array(
             "ar5" => "food",
             "ar87" => "dr",
             "ar21" => "ch",
             "ar443" => "ju"
         ),
         "2" => array(
             "73" => "food",
             "82" => "dr",
             "90" => "ch",
             "2123" => "ju"
         )),
    "ten" => "bar",
    "eleven" => "bar",
    "twelve" => "bar"
);

and am finding all the array keys at a given level like this

foreach ($array['five'] as $keyed=> $user) {
foreach ($user as $key => $value) {
       echo "Key: $key; Value: $value Keyed: $keyed<br />\n";
}
}

However,i would like to get all the found array keys for use in array_key_exists so i need to convert the found keys to array.I am trying that by having this array

function the_keys($val){
foreach ($val['five'] as $keyed=> $user) {
foreach ($user as $key => $value) {
    $keyed = array();
}
}
}

but even that does not cast the found keys into an array as i had thought.What do i need to do to cast the found keys to array?.

So all you care about, in example given, is that x or y get placed into an array for further access at a later time? Not what x or y contain within them, that can be determined later? — aztechy
– aztechy, Commented Sep 7, 2013 at 14:03
So for "level five" you want to have an array('xxx...', 'yyy...') ?? — djot
– djot, Commented Sep 7, 2013 at 14:03
An example of what you want the final output to be would help us understand what you are trying to do. — IMSoP
– IMSoP, Commented Sep 7, 2013 at 14:04

Jimmy T. · Accepted Answer · 2013-09-07 14:02:28Z

3

To get all keys from $val['five'] you can use array_keys():

$keyed = array_keys($val['five']);

You don't need a loop in that case.

answered Sep 7, 2013 at 14:02

Jimmy T.

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Comments

user2672373 · Accepted Answer · 2013-09-07 14:00:26Z

0

Perhaps this would solve your problem

foreach($val['five'] as $arrFive) {
    //Here you have both arrays
    foreach($arrFive as $arrXXXX) {
        //Parse array with index xxxx
    }
    foreach($arrFive as $arrYYYY) {
        //Parse array with index yyyy
    }
}

answered Sep 7, 2013 at 14:00

user2672373

4 Comments

IMSoP Over a year ago

I'm not clear how this would help - you are just looping over the same array ($arrFive) twice...

user2672373 Over a year ago

$arrFive contains both arrays. The inner loop extracts contents of the array with index xxxxxxx, meanwhile the other inner loop extracts contents of the array with index yyyy

IMSoP Over a year ago

That's not what this code does - $arrFive has the same value in both inner loops, so they are both looping over the same data. The first time round the outer loop, $arrFive will be the xxx... array, the second time the yyy... array, but you don't need to write any code twice for that, that's just what a foreach loop does. By having two inner loops, you are simply visiting every item twice.

IMSoP Over a year ago

Here's a live demo based on your code. I've changed the values in the array slightly so that it's a bit easier to see what's going on.

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