Django - how do I clone object without applying clone changes to source object

Question

Best described by example:

View:

def my_view(request):
    obj_old = Inventories.objects.get(id = source_id)
    obj_new = obj_old 
    obj_old.some_field = 0
    obj_old.save()

    obj_new.some_field = 1
    obj_new.id = None
    obj_new.save()

The problem is that the changes I make to obj_new are also applied to obj_old so that the value of some_field is 1 for both obj_old and obj_new. Any ideas how to fix this ?

rafaelc · Accepted Answer · 2016-09-09 19:58:29Z

6

You should make a copy of your object, and not make them equal.

To make a copy you can use the copy module

import copy

obj_new = copy.deepcopy(obj_old)

answered Sep 9, 2016 at 19:58

rafaelc

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