Set array values for specific range in C#

You could write an extension method to make this simpler:

public static class ArrayExt
{
    public static T[] Set<T>(this T[] self, int index, params T[] values)
    {
        Array.Copy(values, 0, self, index, values.Length);
        return self;
    }
}

Using it would look like this:

var s = new uint[64];
s.Set<uint>(0, 2, 4, 6, 3, 1, 7, 8, 9, 7, 11, 37, 32, 19, 16, 178, 2200);

Because Set() returns the array, you can also chain calls like this:

s.Set<uint>( 0, 2, 4, 6, 3, 1, 7, 8, 9, 7, 11, 37, 32, 19, 16, 178, 2200)
 .Set<uint>(16, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14,  15,   16);

Note: The requirement to explicitly put the type into the call comes from the fact that we're using ints in the list of values.

You should really use uint since the destination is uint, then there is no need to specify the type:

var s = new uint[64];
s.Set(0, 2u, 4u, 6u, 3u, 1u, 7u, 8u, 9u, 7u, 11u, 37u, 32u, 19u, 16u, 178u, 2200u);

And of course it works with all types, e.g. string:

var x = new string[64];
x.Set(10, "A", "B", "C");

Not an exact match to the method you described, but you could create a List<int> and use the AddRange() method. Once you've added all the values, you can use to ToArray() method to turn it to an array.

var numbers = new List<int>();
numbers.AddRange(new List<int>{ 2, 4, 6, 3,  1, 7, 8, 9,  7, 11, 37, 32,  19, 16, 178, 2200 });
//numbers.AddRange(new List<int> { ... });

var asArray = numbers.ToArray();

First you define your Arrays

    s1 := { ... }
    s2 := { ... }
    s3 := { ... }
    ...
    sn := { ... }

Then just concat them in a linq method chain

var result = s1.Concat(s2).Concat(s3)....Concat(sn);

You can do it in whatever order you like and get the exact result. It's easy to change the resulting sequence just by altering the chain slightly.

You can do it in a couple ways. Because I do not know you requirements and your code, I know you would need to modify this to suit you. But C# arrays are unlike C++ arrays, so the index always start from zero.

UInt64[] list = {2, 4, 6, 3, 1, 7, 8, 9, 7, 11, 37, 32, 19, 16, 178, 2200,..}; 
//Length of the list must be 31. That is contain 31 numbers.

UInt64[] s= new UInt64[31];

// You can have all the collection  

for (int i = 0; i < list.Length; i++)
{
    s[i] = list[i];
}    

// Or you can modify as below

for (int i = 0; i < 15; i++)
{
    s[i] = list[i];
}

for (int i = 16; i < 31; i++)
{
    s[i] = list[i];
}