PHP - Simple HTML DOM Parser - Getting FATAL ERROR when html is OK

Question

I am trying to parse a table and output the a plaintext in another table. I have gotten this far:

<?php 
    if (url_exists($url))
    {
        $html = file_get_html($url);
    }
    else 
    {
        echo "URL doesn't exist.";
    }

    if ($html && is_object($html) && isset($html->nodes))
    {
        // Everything checks out
        $table = $html->find('table[border]');
        if (!empty($table))
        {
        $row = $table->find('tr');
        }
    }
    else 
    {
        echo "Fetched page is not ok.";
    }
?>

This returns an error: Fatal error: Call to a member function find() on a non-object in /var/www/html/jsudimak/mailman/webdev-test1.php on line 78

Line 78 is this one: $row = $table->find('tr');

This means that :

the html is valid
the table I am trying to parse is also valid

Therefore, I am bewildered by the fact that the find() method is still returning this error.

I have looked into the cause of this error extensively for the past few days and I have yet to find a solution. I have also tried some other parsing tools no still no luck. Help me with this fellow debuggers!!!!

By the way, I am using the Simple HTML Dom Parser to parse the table.

$html->find('table[border]'); and $table->find('tr'); is both these find function in same class ? — Hamza Zafeer
– Hamza Zafeer, Commented Mar 9, 2016 at 14:52
@fusion3k my wrong, I meant $table = $html->find('table[border]')[0]; The documentation says that, unless you specify an index in the function find(), it will return an array — Nadir
– Nadir, Commented Mar 9, 2016 at 14:53

Nadir · Accepted Answer · 2016-03-09 15:49:59Z

2

Use $table = $html->find('table[border]')[0];

The documentation says that, unless you specify an index in the function find(), it will return an array

answered Mar 9, 2016 at 15:49

Nadir

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