Docker Compose - Image name

Question

When you are running a docker-compose up -d command, by default the build image is going to take the name of the current folder.

So for example for this docker-compose.yml file my image will be named: dockersymfony_php because my current folder is named docker-symfony and I indicated php for my image in my yaml file

php:
    build: ./docker/php
    container_name: symfony

Is there a way to override that ? Like container_name to renaming the container...

I know that the command docker build -t . can do it but I need to use my docker-compose.yml file.

taco · Accepted Answer · 2015-12-20 18:48:42Z

8

Currently all you can do is customize the project name (the first part of the name before the underscore) using -p flag:

docker-compose -p COMPOSE_PROJECT_NAME

In the next release you'll be able to use image to set the name: https://github.com/docker/compose/issues/2092

edited Dec 20, 2015 at 18:48

taco

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answered Dec 17, 2015 at 22:51

dnephin

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3 Comments

taco Over a year ago

What version of docker-compose supports this? Doesn't work with 1.5.2 build 7240ff3.

dnephin Over a year ago

supports which? Setting the project name has always been supported. The linked issue will be in 1.6.0

taco Over a year ago

You're right. Maybe I ran docker instead of docker-compose.

Nilesh Gule · Accepted Answer · 2018-01-14 04:14:49Z

2

As of Jan 2018, with version 3 of Docker compose you can use container_name to specify the name. An example can be found here https://www.handsonarchitect.com/2018/01/docker-compose-tip-how-to-avoid-sql.html

answered Jan 14, 2018 at 4:14

Nilesh Gule

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