Python method overload based on argument count?

Question

If I call QApplication's init without arguments i get

TypeError: arguments did not match any overloaded call:
  QApplication(list-of-str): not enough arguments
  QApplication(list-of-str, bool): not enough arguments
  QApplication(list-of-str, QApplication.Type): not enough arguments
  QApplication(Display, int visual=0, int colormap=0): not enough arguments
  QApplication(Display, list-of-str, int visual=0, int cmap=0): not enough arguments

very interesting! How can I write a class like that?? I mean, every trick for this kind of function overloading I saw did not involve explicit signatures.

user395760 · Accepted Answer · 2010-08-05 21:40:54Z

3

TypeError is just another Exception. You can take *args **kwargs, check those, and raise a TypeError yourself, specify the text displayed - e.g. listing the expected call.

That being said, PyQt is a bunch of .pyd == native python extension, written in C or C++ (using Boost::Python). At least the latter supports "real" overloads afaik.

Either way, you shouldn't do this unless you have a really good reason. Python is duck-typed, embrace it.

answered Aug 5, 2010 at 21:40

user395760

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Amber · Accepted Answer · 2010-08-05 21:27:50Z

0

It's quite possible that its init is simply using __init__(self, *args, **kwargs) and then doing its own signature testing against the args list and kwargs dict.

answered Aug 5, 2010 at 21:27

Amber

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