Finding a version number using grep

Question

Basically i am creating an update checker for emesene on osx. I need to find out the version number from inside this file: http://emesene.svn.sourceforge.net/viewvc/emesene/trunk/emesene/Controller.py

The version number is found at self.VERSION = 'version' in the file e.g. self.VERSION = '1.6.3'

The version number then needs to be saved in a file

Is this possible using grep?

Amardeep AC9MF · Accepted Answer · 2010-07-14 20:57:17Z

2

grep "self.VERSION = '.*'" Controller.py | cut -d "'" -f 2 > file

answered Jul 14, 2010 at 20:48

Amardeep AC9MF

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Comments

camh · Accepted Answer · 2010-07-14 23:50:49Z

2

If you can use sed(1), then you can extract it with a single command:

sed -n "s/.*self\.VERSION = '\([^']*\)'.*/\1/p" Controller.py > file

answered Jul 14, 2010 at 23:50

camh

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ghostdog74 · Accepted Answer · 2010-07-15 01:05:24Z

1

you can use awk,

$ awk -F"['-]" '/VERSION[ \t]=/{print $2}' Controller.py
1.6.3

answered Jul 15, 2010 at 1:05

ghostdog74

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