Returning json data from php to ajax

Question

I'm trying to get a json object from php so I can work with it in ajax. Here is my ajax code:

 $.ajax({
   type: 'get',
   url: eventsListPath,
   dataType : "json",
   data: {},
   success: function (data) {
       $('#eventInformation').html(data.table);
       alert(data.table);
   }
});

And my PHP:

$obj->table="hey";
echo json_encode($obj, JSON_UNESCAPED_SLASHES);

But the line

alert(data.table);

comes back with 'undefined'. Any ideas?

Try console.log(data) in success. Tell me the result.

iplus26
– iplus26

2015-08-10 06:59:49 +00:00
Commented Aug 10, 2015 at 6:59 — iplus26
– iplus26, Commented Aug 10, 2015 at 6:59

Harish Lalwani · Accepted Answer · 2015-08-10 07:09:44Z

1

Try this in your php code. Json encode an array.

$obj['table']="hey";
echo json_encode($obj, JSON_UNESCAPED_SLASHES);

Alternate - Or your class should be like this

class your_classname
{
  public $table;
 //other class related code
}
$obj = new your_classname;

$obj->table="hey";
echo json_encode($obj, JSON_UNESCAPED_SLASHES);

edited Aug 10, 2015 at 7:09

answered Aug 10, 2015 at 6:58

Harish Lalwani

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1 Comment

Harish Lalwani Over a year ago

please do mark my answer as correct if the code helped you. thanks @Steven Jacks

Kamuran Sönecek · Accepted Answer · 2015-08-10 07:12:04Z

1

if I'm not mistaken, json_encode just works for arrays

$obj = [{table:"hey"}];

answered Aug 10, 2015 at 7:12

Kamuran Sönecek

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Comments

Voro · Accepted Answer · 2015-08-10 07:17:03Z

0

<?php
$obj = new stdClass();
$obj->table="hey";
echo json_encode($obj)

produces

{"table":"hey"}

Check it using Firebug. Also check the content-type, should be Content-Type: application/json

answered Aug 10, 2015 at 7:17

Voro

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Comments

jinglebird · Accepted Answer · 2015-08-10 07:37:28Z

0

you must pass array to json_encode not object

<?php
$array['table'] = "hey";
echo json_encode($array, JSON_UNESCAPED_SLASHES);

answered Aug 10, 2015 at 7:37

jinglebird

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