Reading Lines of Input into Array in Scala?

Question

I have 10 lines of input I am reading from stdin via readLine(). How can I read these 10 lines into an array of strings?

jwvh · Accepted Answer · 2015-06-10 04:06:52Z

3

A slightly more direct approach:

Array.fill(10){readLine()}

answered Jun 10, 2015 at 4:06

jwvh

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Akos Krivachy · Accepted Answer · 2015-06-10 00:41:48Z

1

You can create a range from 1 to 10 with 1 to 10 and then map over it while not caring about the actual numbers, only reading lines:

(1 to 10).map(_ => readLine()).toArray

As asked in your comment, printing out arrays easily can't be done just by calling println on them, but Seqs support it:

scala> println(Array("a", "b", "c"))
[Ljava.lang.String;@60b85ba1

scala> println(Seq("a", "b", "c"))
List(a, b, c)

edited Jun 10, 2015 at 0:41

answered Jun 10, 2015 at 0:37

Akos Krivachy

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3 Comments

user4992519 Over a year ago

I had tried this already actually and when I printed it, it gave me a bunch of gibberish for some reason: [Ljava.lang.String@bunch of numbers

Akos Krivachy Over a year ago

Because Array is just a Java array meaning the toString method is a default method and prints the type + hashCode. Use .toSeq instead to get a Scala sequence. Updated my answer with examples.

dhg Over a year ago

To print out an array, try: a.mkString(", ")

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