I am trying following but getting error "variable arr of type Array[Int] does not take type parameters."
object try_arr
{
def main(args: Array[String])
{
var arr = new Array[Int](3)
for(i<- 1 to 3)
{
val num = scala.io.StdIn.readInt()
arr[i] = num
}
}
}
As already pointed out by Simon, you're trying to apply java syntax to scala code -- in scala [ ] are used to specify type and in order to access array elements you're shall use (), e.g. xs(3)
I guess the cleanest way to solve this is to make use of Array.fill method:
object FillTheArray {
def main(args: Array[String]) {
val userInput = Array.fill(3) {
scala.io.StdIn.readInt()
}
}
}
In scala you index the array like this
arr(i) = num
Use below statement
a(i)= scala.io.StdIn.readInt()
More of a side note, consider this more Scalish approach with immutable objects,
val xs = for (i <- 1 to 3; num = scala.io.StdIn.readInt()) yield num
where each value in the range (1 to 3) is mapped onto a user input. The resulting vector (xs) may be converted to an array,
xs.toArray
Likewise
(1 to 3).map(_ => scala.io.StdIn.readInt()).toArray
proves terser a code.
This is in contrast with the more imperative approach to creating a mutable array, and updating each position (referred by each value in the range) with a user input.
in for loop can't 1 to 3 because array index start in 0 and beetween 0 to 2. Else shows error ArrayOutOfBound Exception.
Code : var arr = new ArrayInt
for(i<- 0 to 2)
{
print("Enter number")
val num = scala.io.StdIn.readInt()
arr(i) = num
}
arr.foreach((element:Int)=> print(element + " "))
