python open file error

Question

I am trying to open some file and I know there are some errors in the file with UTF-8 encoding, so what I will do in python3 is

open(fileName, 'r', errors = 'ignore')

but now I need to use python2, what are the corresponding way to do this?

Below is my code after changing to codecs

    with codecs.open('data/journalName1.csv', 'rU', errors="ignore") as file:
        reader = csv.reader(file)
        for line in reader:
            print(line)

And file is here https://www.dropbox.com/s/9qj9v5mtd4ah8nm/journalName.csv?dl=0

It is not the problem with the file, a lot of file can cause error, I am just asking how to cope with the error. — 1a1a11a
– 1a1a11a, Commented Jun 8, 2015 at 2:14

washcloth · Accepted Answer · 2015-06-08 01:37:36Z

8

Python 2 does not support this using the built-in open function. Instead, you have to uses codecs.

import codecs
f = codecs.open(fileName, 'r', errors = 'ignore')

This works in Python 2 and 3 if you decide you need to switch your python version in the future.

answered Jun 8, 2015 at 1:37

washcloth

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2 Comments

1a1a11a Over a year ago

It is still not correct, "UnicodeDecodeError: 'utf-8' codec can't decode byte 0xe6 in position 2028: invalid continuation byte" there is still error, I am going to add my code and upload file.

1a1a11a Over a year ago

Actually I just copy the lines into another file, there is no error, but for this file, if I used the old way in python3, it can pass, but using codecs.open in python2, there is still error, please help me, thank you!

Alex Ivanov · Accepted Answer · 2015-06-08 02:21:11Z

1

For UTF-8 encoded files I would suggest io module.

#!/usr/bin/python
# -*- coding: utf-8 -*-

import io

f=io.open('file.txt', 'r',  encoding='utf8')
s=f.read()
f.close()

answered Jun 8, 2015 at 2:21

Alex Ivanov

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2 Comments

washcloth Over a year ago

some errors in the file with UTF-8 encoding means that it really itsn't a pure UTF-8 file.

Alex Ivanov Over a year ago

My guess was the OP got an error: "UnicodeEncodeError: 'ascii' codec can't encode character u'\xa0' in position 20: ordinal not in range(128)" or the like. It happens sometimes with UTF-8 decoded strings. Such an error is usually fixed by encoding in UTF-8, not ASCII.

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