Variable object properties in PHP

Question

I have an object $var which has 3 properties one two three. I'm trying to store the properties in an array $info.

The long way:

$info['one'] = $var->one;
$info['two'] = $var->two;
$info['three'] = $var->three;

At some point in the future the 3 properties will become many more so I'm trying to store the properties in my array using a foreach loop.

$attributes = array( 'one', 'two', 'three' );

foreach ( $attributes as $attribute ) {
    $info[$attribute] = $var->$attribute; // My problem is here
}

The problem I'm having is you can't do this: $var->$attribute.

How can I use a variable for my object's property?

Why shouldn't you be able to do that? Do you get any errors? The code works fine for me. — Rizier123
– Rizier123, Commented Apr 12, 2015 at 20:17
Try $var->{$attribute} or I would just do $info = get_object_vars($var). — AbraCadaver
– AbraCadaver, Commented Apr 12, 2015 at 20:20
@henrywright I would say that's the way to do it! (OR use ^ get_object_vars() as AbraCadaver mentioned) — Rizier123
– Rizier123, Commented Apr 12, 2015 at 20:25
@henrywright : what is Rizier123 saying is that, if what you show is the real word example, your snippet of code does work properly. If it does not, that means, you have another problem you are not showing us. — β.εηοιτ.βε
– β.εηοιτ.βε, Commented Apr 12, 2015 at 20:29

AbraCadaver · Accepted Answer · 2015-04-12 20:33:10Z

1

Your current code works fine, or I would just do:

$var = new someObj;
$attributes = array( 'one', 'two', 'three' );
$info = array_intersect_key(array_flip($attributes), get_object_vars($var));

edited Apr 12, 2015 at 20:33

answered Apr 12, 2015 at 20:29

AbraCadaver

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2 Comments

henrywright Over a year ago

what's the difference between $var->{$attribute} and $var->$attribute?

AbraCadaver Over a year ago

On beer 5 I'm going to step away for now :-)

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