Bash while is not working as expected - String comparison

Question

I have been stuck for an hour now and still can't figure this out. FYI - I am new to the bash scripting. Here is what I am trying to do

var="Y"
while [ "$var" = "Y"]
do
echo "Hello World!!"
echo "Keep going? [Y/N]"
read var
done

I am getting an error in the while line (while [ "$var" = "Y"]) - I pretty much tried everything - with single ', double " - no "

Possible duplicate of stackoverflow.com/questions/12840769/… — tripleee
– tripleee, Commented Jan 24, 2015 at 8:40
Did you actually read and try to understand the error given? When I run your script I get: ./script: line 4: [: missing `]'. Trying to read the error message can help. — gniourf_gniourf
– gniourf_gniourf, Commented Jan 24, 2015 at 9:30

Avinash Raj · Accepted Answer · 2015-01-24 07:27:00Z

1

You need to provide a space next to "Y"

That is,

while [ "$var" = "Y" ]

answered Jan 24, 2015 at 7:27

Avinash Raj

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