Reverse sort a 2d numpy array in python

Question

I have a numpy array like:

A = array([[-inf,  4,  5,  10, -inf, 1],
            [-inf,  2,  6, 8, -inf, 1],
            [-inf,  4,  -inf,  10, -inf, 100]
      ])

I need to sort in a decreasing order: 

A = array ([ 10,5,4,1,-inf,-inf], 
          [8,6,2,1,-inf,-inf],
           [100,10,4,-inf,-inf,-inf]])

Here -inf is float('-inf') How Do I do this?

I tried this: sorted(A, key=lambda listA: len(listA), reverse=True)

But I am not getting the sorted array. Can someone please tell me how to do this?

Eric O. Lebigot · Accepted Answer · 2014-11-21 05:13:36Z

5

How about

A.sort()
A[:,::-1]

?

References :

http://docs.scipy.org/doc/numpy/reference/generated/numpy.ndarray.sort.html

http://docs.scipy.org/doc/numpy/reference/arrays.indexing.html

edited Nov 21, 2014 at 5:13

Eric O. Lebigot

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answered Nov 21, 2014 at 5:03

Jules Gagnon-Marchand

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3 Comments

fjarri Over a year ago

Since his array is 2D, it'll be rather [:,::-1].

learner Over a year ago

I am getting :TypeError: 'NoneType' object is not subscriptable

Akavall Over a year ago

A.sort() sorts array in place.

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