I have two numpy arrays with number (Same length), and I want to count how many elements are equal between those two array (equal = same value and position in array)
A = [1, 2, 3, 4]
B = [1, 2, 4, 3]
then I want the return value to be 2 (just 1&2 are equal in position and value)
Using numpy.sum:
>>> import numpy as np
>>> a = np.array([1, 2, 3, 4])
>>> b = np.array([1, 2, 4, 3])
>>> np.sum(a == b)
2
>>> (a == b).sum()
2
a = np.array([[1,2,0],[3,4,0]]); b = np.array([[1,9,0],[9,4,0]]); print((a == b).sum()) 
b = np.array([3, 2, 4, 1, 1])np.sum(a[:min(len(a), len(b))] == b[:min(len(a), len(b))])
'bool' object has no attribute 'sum'As long as both arrays are guaranteed to have the same length, you can do it with:
np.count_nonzero(A==B)
s = min(len(A), len(B)); count = np.count_nonzero(A[:s] == B[:s]).np.count_nonzero(np.logical_or.reduce(A[:, np.newaxis], B[np.newaxis, :], axis=0)).