How to capture the output of curl to variable in bash [duplicate]

Question

So, lets say I have the following command:

curl -I http://google.com | head -n 1| cut -d $' ' -f2

This will capture the http status code?? Now I want to assign this to variable.. in bash script

like output = "curl -I http://localhost:8088/tracks?key=9 | head -n 1| cut -d $' ' -f2"

or something like that..

How do I assign the response of above command to a variable called output in bash? Thanks

try surrounding the command in back ticks

Bohemian
– Bohemian ♦

2014-08-15 03:44:53 +00:00
Commented Aug 15, 2014 at 3:44 — Bohemian
– Bohemian ♦, Commented Aug 15, 2014 at 3:44

Ilan.b · Accepted Answer · 2021-02-22 02:06:55Z

53

You have two options (see this StackOverflow answer here):

Preferred: Surround the invocation in $()
Surround the invocation in back ticks

NOTE: back ticks are legacy, the former method is preferred.

output=$(curl -I http://google.com | head -n 1| cut -d $' ' -f2)
echo "$output";

output=`curl -I http://google.com | head -n 1| cut -d $' ' -f2`
echo "$output";

edited Feb 22, 2021 at 2:06

Ilan.b

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answered Aug 15, 2014 at 3:48

user3920237

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Siddharth Over a year ago

Is there a way to return value of eval command? Nothing works from all tried on SO

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