CSharpCodeProvider: Why is a result of compilation out of context when debugging

Question

I have following code snippet that i use to compile class at the run time.

//now compile the runner
var codeProvider = new CSharpCodeProvider(
  new Dictionary<string, string>() { { "CompilerVersion", "v3.5" } });

string[] references = new string[]
  {
    "System.dll", "System.Core.dll", "System.Core.dll"
  };
CompilerParameters parameters = new CompilerParameters();

parameters.ReferencedAssemblies.AddRange(references);               
parameters.OutputAssembly = "CGRunner";
parameters.GenerateInMemory = true;
parameters.TreatWarningsAsErrors = true;

CompilerResults result = codeProvider.CompileAssemblyFromSource(parameters, template);

Whenever I step through the code to debug the unit test, and I try to see what is the value of "result" I get an error that name "result" does not exist in current context. Why?

Are you debugging in release mode? This may happen to optimizations of unused variable. — Elisha
– Elisha, Commented Mar 19, 2010 at 19:24
No, I am not, it is in debug mode. Reason I am debugging is because next line is supposed to load assembly and use Activator.CreateInstance, but it cannot find it so it throws an error. — epitka
– epitka, Commented Mar 19, 2010 at 19:27
You wanna post your question as an answer, slightly modified. I had "Optimize Code" checked in project build properties. Your "optimizations of unused variable" gave an idea to check that. — epitka
– epitka, Commented Mar 19, 2010 at 19:31
@Elisha - this comment only exists (with the @prefix) to draw your attention to @epitka's comment ("post that as an answer"). — Marc Gravell
– Marc Gravell, Commented Mar 19, 2010 at 19:39
for info, if you want to make sure another user sees your reply to their comment, use the @prefix - then it shows in their messages area (only works for the first @whatever in your comment, though) — Marc Gravell
– Marc Gravell, Commented Mar 19, 2010 at 19:40

Elisha · Accepted Answer · 2010-03-19 19:56:18Z

1

Are you debugging in release mode? This may happen to optimizations of unused variable.

For example:

public void OptimizedMethod()
{
    int x = 5; // In optimized mode it's not possible to watch the variable
}

Code optimization happens when running in release mode, or when setting "Optimize code" in project properties (under build tab)

edited Mar 19, 2010 at 19:56

answered Mar 19, 2010 at 19:50

Elisha

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