Executing output of python from loop in bash

Question

I wrote a bash that has python command included in loop: (part of script)

#!/bin/bash

ARG=( $(echo "${@:3}"))
for (( i=1; i<=$#-3; i++ ))
do
python -c "print('<Command with variables>' * 1)"
done

When I run it, depends on number of my args for example I have this output:

nohup command-a &
nohup command-b &
nohup command-c &

How do I execute the output lines from bash immediately?

Can I tell python command to run them in each iteration? How?

Thank you

Theolodis · Accepted Answer · 2014-05-28 09:32:02Z

1

You can achieve that by executing the python code in a sub-shell and evaluating the content of that shell afterwards.

eval $(python -c ...)

$() returns a string you can evaluate with eval

Theolodis

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answered May 28, 2014 at 8:55

ElefEnt

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Comments

choroba · Accepted Answer · 2014-05-28 08:13:06Z

0

You are asking two questions. I can only answer the first one:

If you want to run commands coming to the standard output, just redirect them to bash:

python -c 'print "ls"' | bash

answered May 28, 2014 at 8:13

choroba

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Ok, Your answer is good for my two questions...So I can do it:do python -c "('nohup <command> &') * 1" | bash and it should work