'SyntaxError: Unexpected token o' with angularjs

Question

It gaves me error when I m trying to call this controller .

hiren.controller('hirenz' , function($scope , $http , $location , $routeParams){
    $http.post((rootURL + "music") , {'alpha' : $routeParams.alpha , 'name' : $routeParams.name ,
        'album' : $routeParams.albumname }).success(function(data){
        var parsedJson = JSON.parse(data) ;
        console.log(parsedJson.name);
    });
});

Here is the "data" that i am calling from server

{
    "name": [
        "Adhar - Adhar ",
        "Adhar - Adhare Opshori ",
        "Adhar - Aj Neshay "
    ],
    "url": [
        "http://music-com-bd.com/Music/A/Adhar/Adhare Opshori/Adhar - Adhar (music.com.bd).mp3",
        "http://music-com-bd.com/Music/A/Adhar/Adhare Opshori/Adhar - Adhar (music.com.bd).mp3",
        "http://music-com-bd.com/Music/A/Adhar/Adhare Opshori/Adhar - Adhar (music.com.bd).mp3"
    ]
}

'SyntaxError: Unexpected token o'

pyprism
– pyprism

2014-01-23 12:17:55 +00:00
Commented Jan 23, 2014 at 12:17 — pyprism
– pyprism, Commented Jan 23, 2014 at 12:17

Jayram · Accepted Answer · 2014-01-23 12:22:58Z

10

You are parsing something which is not a string. It might be already in form of JSON object. You do not need to parse it. If you change var parsedJson = JSON.parse(data) ; to var parsedJson = data; The error will go off.

answered Jan 23, 2014 at 12:22

Jayram

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Comments

Alex Postnikov · Accepted Answer · 2014-10-21 14:16:03Z

3

This error occurs when JSON is not properly formed. Check it with JSLint

answered Oct 21, 2014 at 14:16

Alex Postnikov

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