Jquery JavaScript variable is not defined, inexperience caused error

Question

So I am new to JavaScript and jQuery and I can't figure out why my variables are "undefined."

This is what I am doing: http://jsfiddle.net/krECX/15/

What I don't understand is why the variable $asdf is undefined when I call the $asdf.length in this function:

function func() {
   var $asdf = $('#inp').value;
   $('#divOfDoom').hide().html("" + $asdf.length).fadeIn('fast');
}

I'm sure I'm doing something stupid but every example I have found does something identical to my eyes.

What I have tried: var $asdf = createInstance(); alert('' + $asdf); returns 'undefined' regardless of what is in the input box.

Any advice is appreciated.

Spokey · Accepted Answer · 2013-07-23 14:42:25Z

5

var $asdf = $('#inp')[0].value

or

var $asdf = $('#inp').val()

answered Jul 23, 2013 at 14:42

Spokey

11k2 gold badges31 silver badges44 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Reinstate Monica Cellio Over a year ago

@sparks Mixing jQuery and JavaScript is a problem that lots of people have trouble with even when they're only new to 1 side of the coin! Keep it up ;)

karaxuna · Accepted Answer · 2013-07-23 14:42:35Z

3

Incorrect jQuery syntax:

$('#inp').val();

answered Jul 23, 2013 at 14:42

karaxuna

26.9k13 gold badges86 silver badges120 bronze badges

Collectives™ on Stack Overflow

Jquery JavaScript variable is not defined, inexperience caused error

2 Answers 2

1 Comment

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

1 Comment

Comments

Your Answer

Sign up or log in

Post as a guest

Related